Sample Proof on Triangle Congruence Part 2

This is the second part on a series of posts on worked proofs in Triangle Congruence. In this post, we prove another problem.
triangle congruence

Given: $latex \overline{AB}$ and $latex \overline{CD}$ bisect each other at $latex E$.
Prove: $latex AD \cong BC$ 

A bisector divides a segment into equal parts. Now, since $latex AB$ and $latex CD$ bisect each other,
$latex AE = BE$ and $latex CE = DE$ by definition of bisector.

We also know that
$latex \angle AED \cong \angle CEB$ because vertical angles are congruent.

triangle congruence2

Now, since the angle is between the congruent sides,
$latex \triangle AED \cong \triangle BEC$ by SAS congruence.

Therefore, $latex AD \cong BC$ since corresponding sides of congruent triangles are congruent.

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